A sphere of radius \(1m\) and mass \(25 Kg\) is put on another sphere of radius \(5 m\) and \(7 Kg\) which is placed on a smooth ground. Now the upper sphere is pushed very slightly from it's equilibrium position and it begins to fall.
Now when the line joining the centre of the 2 spheres makes an angle \(\theta \) with the vertical the upper sphere loses contact with lower sphere. Then find \(\theta \) in degrees to 1 decimal place.
Details and assumptions:
1)There is no friciton between the two spheres.
2)Take \(g={ 9.8\quad m/s }^{ 2 }.\)
by
Ronak Agarwal
