At \(20^\circ\text{C}\), a \(200\text{ g}\) saturated \(\ce{NaCl}\) solution is heated until \(40\text{ g}\) of water is evaporated. Then, the solution is cooled down back to \(20^\circ\text{C}\). What is the mass of \(\ce{NaCl}\) that is separated out from the solvent in grams?
Details and Assumptions:
The solubility of \(\ce{NaCl}\) at \(20^\circ\text{C}\) is \(36\text{ g}/100\text{ g}\) water