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## A Daring Rescue

If you’ve ever watched a duck swim furiously upriver without appearing to move or a seagull fly directly into a gale without getting anywhere, you already have an idea about relative velocity. Relative to you, the duck or the gull doesn’t seem to be moving very much at all, but relative to the water or the air, they are moving pretty quickly.

But which viewpoint is the right one? Are they moving or stationary? Does it even matter?

Proto-physicist Galileo Galilei taught us it actually doesn't matter. Both viewpoints are equally valid — it is meaningless to say that we are stationary and the water is moving, or vice versa. After all, we are all standing on Earth, which is moving at around $\SI{31}{\kilo\meter}$ per second relative to the Sun, which is moving at around $\SI{220}{\kilo\meter}$ per second relative to the center of our galaxy, and so on.

But just because all viewpoints are valid, that doesn’t make them all equally useful.

Consider a duck in a river chasing a scrap of bread. From the perspective of someone on the bank, the duck has to make a tricky calculation to intercept the bread, which is moving downstream. But from the point of view of the duck carried by the same current, the bread is sitting still and the duck just needs to swim towards it.

Here the reference frame of the water is more useful than the reference frame of the ground.

If the duck is aiming for a point directly across the river on the bank, then it might be better off thinking in the bank’s reference frame. It needs to paddle diagonally upstream in order to follow a horizontal line in that frame.

On the widget above, you can toggle between the reference frames of the bank and the water. You can see for yourself that the distance the duck will have to paddle through the water is greater than the length of the actual path it follows in the frame of the bank.

To understand this, just think about how much paddling the duck would do to stay in one place according to someone on the bank. If the speed of the river is $v_\text{river}$ and the duck is stationary for time $T,$ then relative to the water, the duck has paddled a distance of $v_\text{river}T,$ despite not having moved relative to the bank. Motion directly across the river adds to this distance.

Things get more complicated if the river isn’t all flowing at the same speed. A real river usually flows faster in the center than near the bank. In this situation, a duck may be able to get to its target the fastest by getting itself into faster- or slower-moving water and taking a route that looks far from the shortest from above. Through the water, though, a faster route is a shorter one.

# Today's Challenge

While paddling, you notice an ill-equipped day-tripper is stuck in the rising water. You are the only one around to help them, and you need to paddle to them as quickly as possible.

From the bank, the water is moving with speed $V_\text{river}=\SI[per-mode=symbol]{4}{\meter\per\second},$ which is the same speed you can paddle through the water. Within $d=\SI{10}{\meter}$ of the bank, the current is negligible. To make the rescue, you angle a distance $h$ upstream before entering the current.

To reach the stranded hiker in the least time, how far upriver $(h)$ should you go before entering the current?

Hint: One way to write the rescue time $T$ is $T=A\cdot\sqrt{d^2+h^2}+B\cdot h+C\cdot \frac1h,$ where $A, B,$ and $C$ are numbers that depend on $V_\text{river}$ and $d.$ You may enter their values into the graphing tool below and identify the optimal value for $h:$ $\\[1em]$

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