@Yannawat Praserttham
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Combine it into a single fraction, you have \( \dfrac{4\cdot 10^{301} + 3}{10^{301}} \). Notice that neither e numerator nor the denominator is not a perfect square (do you know how to prove that?), so your final answer is simply \( \left( \dfrac{4\cdot 10^{301} + 3}{10^{301}} \right)^{1/16} \).

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TopNewestWhat are you looking for exactly? The simplest form of the answer? The first few digits of the number?

If you're looking for the first few digits of the number, try \((1+x)^n \approx 1 + nx\). for small \(x\).

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The simplest form of the answer.

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Hint: convert decimal number into an improper fraction.

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= \(\frac{4 \times 10^{301}}{10^{301}}+\frac{3}{10^{301}}\)

= \(4+\frac{3}{10^{301}}\)

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