@Yannawat Praserttham
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Combine it into a single fraction, you have \( \dfrac{4\cdot 10^{301} + 3}{10^{301}} \). Notice that neither e numerator nor the denominator is not a perfect square (do you know how to prove that?), so your final answer is simply \( \left( \dfrac{4\cdot 10^{301} + 3}{10^{301}} \right)^{1/16} \).
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Pi Han Goh
·
9 months, 3 weeks ago

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TopNewestWhat are you looking for exactly? The simplest form of the answer? The first few digits of the number?

If you're looking for the first few digits of the number, try \((1+x)^n \approx 1 + nx\). for small \(x\). – Pi Han Goh · 9 months, 4 weeks ago

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– Yannawat Praserttham · 9 months, 4 weeks ago

The simplest form of the answer.Log in to reply

– Pi Han Goh · 9 months, 3 weeks ago

Hint: convert decimal number into an improper fraction.Log in to reply

– Yannawat Praserttham · 9 months, 3 weeks ago

I did that, but i don't know what to do next.Log in to reply

– Pi Han Goh · 9 months, 3 weeks ago

Show me what you've done so far.Log in to reply

= \(\frac{4 \times 10^{301}}{10^{301}}+\frac{3}{10^{301}}\)

= \(4+\frac{3}{10^{301}}\) – Yannawat Praserttham · 9 months, 3 weeks ago

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– Pi Han Goh · 9 months, 3 weeks ago

Combine it into a single fraction, you have \( \dfrac{4\cdot 10^{301} + 3}{10^{301}} \). Notice that neither e numerator nor the denominator is not a perfect square (do you know how to prove that?), so your final answer is simply \( \left( \dfrac{4\cdot 10^{301} + 3}{10^{301}} \right)^{1/16} \).Log in to reply