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# Dots

$$\sqrt{\sqrt{\sqrt{\sqrt{4.\underbrace {00\dots}_{300}3}}}}$$ = ?

Note by Yannawat Praserttham
11 months, 1 week ago

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What are you looking for exactly? The simplest form of the answer? The first few digits of the number?

If you're looking for the first few digits of the number, try $$(1+x)^n \approx 1 + nx$$. for small $$x$$. · 11 months, 1 week ago

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The simplest form of the answer. · 11 months, 1 week ago

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Hint: convert decimal number into an improper fraction. · 11 months, 1 week ago

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I did that, but i don't know what to do next. · 11 months ago

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Show me what you've done so far. · 11 months ago

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$$4.\underbrace {00\dots}_{300}3$$ = $$\frac{(4 \times 10^{301})+3}{10^{301}}$$

= $$\frac{4 \times 10^{301}}{10^{301}}+\frac{3}{10^{301}}$$

= $$4+\frac{3}{10^{301}}$$ · 11 months ago

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Combine it into a single fraction, you have $$\dfrac{4\cdot 10^{301} + 3}{10^{301}}$$. Notice that neither e numerator nor the denominator is not a perfect square (do you know how to prove that?), so your final answer is simply $$\left( \dfrac{4\cdot 10^{301} + 3}{10^{301}} \right)^{1/16}$$. · 11 months ago

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