Hrishikesh pingle ur 2ndstep is wrong coz u r cancelling zero with another
–
Sukesh S
·
1 year ago

Log in to reply

Sorry its not firat .
Its first
–
Mukul Sharma
·
1 year, 10 months ago

Log in to reply

In the firat step.you considered a= b and in the second last step there are terms a-b on both sides thus lhs = rhs = 0
There is nothing like 2=1.
–
Mukul Sharma
·
1 year, 10 months ago

Log in to reply

in second step u have aded 'a' on both sides.then why can't u subtract 'b' from both sides,which implies a-b=0.so u can't cancel a-b with a-b. GOT IT?
–
Pranshul Srivastav
·
1 year, 11 months ago

Log in to reply

you second last step is incorrect coz you are cancelling a zero with another zero
–
Pranshul Srivastav
·
1 year, 11 months ago

@Krishna Sharma
–
but.. a-b becomes zero when we substitute either 'a' for 'b' or 'b' for 'a' without substituting we can cancel a-b...
–
Hrishikesh Pingle
·
1 year, 11 months ago

@Hrishikesh Pingle
–
Look, if its value is zero then it is zero one cannot argue that writing it into other form willchange its value

For example let \(h = 0\)

\(\dfrac{h}{h} =? \)

You cannot say that it is just "h" so cancel it, you cannot. Because \(\frac{0}{0}\) don't have a specific value.
–
Krishna Sharma
·
1 year, 11 months ago

Log in to reply

i don't think that it is necessary to substitute values,every time...
–
Hrishikesh Pingle
·
1 year, 11 months ago

## Comments

Sort by:

TopNewestHrishikesh pingle ur 2ndstep is wrong coz u r cancelling zero with another – Sukesh S · 1 year ago

Log in to reply

Sorry its not firat . Its first – Mukul Sharma · 1 year, 10 months ago

Log in to reply

In the firat step.you considered a= b and in the second last step there are terms a-b on both sides thus lhs = rhs = 0 There is nothing like 2=1. – Mukul Sharma · 1 year, 10 months ago

Log in to reply

in second step u have aded 'a' on both sides.then why can't u subtract 'b' from both sides,which implies a-b=0.so u can't cancel a-b with a-b. GOT IT? – Pranshul Srivastav · 1 year, 11 months ago

Log in to reply

you second last step is incorrect coz you are cancelling a zero with another zero – Pranshul Srivastav · 1 year, 11 months ago

Log in to reply

– Hrishikesh Pingle · 1 year, 11 months ago

we haven't substituted 'a' for 'b' or 'b' for 'a' so we cant say it is a zeroLog in to reply

– Krishna Sharma · 1 year, 11 months ago

Your First step says \(a=b\) so you are actually canceling zero.Log in to reply

– Hrishikesh Pingle · 1 year, 11 months ago

but.. a-b becomes zero when we substitute either 'a' for 'b' or 'b' for 'a' without substituting we can cancel a-b...Log in to reply

\(a= b\)

Take \(b\) on LHS

\(a-b = 0\). – Krishna Sharma · 1 year, 11 months ago

Log in to reply

– Hrishikesh Pingle · 1 year, 11 months ago

but why take b on LHS ???Log in to reply

– Krishna Sharma · 1 year, 11 months ago

Just to explain you that it is zero without substitution.Log in to reply

– Hrishikesh Pingle · 1 year, 11 months ago

is it necessary to solve a-b , i mean without solving we can cancel itLog in to reply

For example let \(h = 0\)

\(\dfrac{h}{h} =? \)

You cannot say that it is just "h" so cancel it, you cannot. Because \(\frac{0}{0}\) don't have a specific value. – Krishna Sharma · 1 year, 11 months ago

Log in to reply

i don't think that it is necessary to substitute values,every time... – Hrishikesh Pingle · 1 year, 11 months ago

Log in to reply