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# 1=2

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Note by Hrishikesh Pingle
2 years, 4 months ago

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Hrishikesh pingle ur 2ndstep is wrong coz u r cancelling zero with another · 1 year, 6 months ago

Sorry its not firat . Its first · 2 years, 4 months ago

In the firat step.you considered a= b and in the second last step there are terms a-b on both sides thus lhs = rhs = 0 There is nothing like 2=1. · 2 years, 4 months ago

in second step u have aded 'a' on both sides.then why can't u subtract 'b' from both sides,which implies a-b=0.so u can't cancel a-b with a-b. GOT IT? · 2 years, 4 months ago

you second last step is incorrect coz you are cancelling a zero with another zero · 2 years, 4 months ago

we haven't substituted 'a' for 'b' or 'b' for 'a' so we cant say it is a zero · 2 years, 4 months ago

Your First step says $$a=b$$ so you are actually canceling zero. · 2 years, 4 months ago

but.. a-b becomes zero when we substitute either 'a' for 'b' or 'b' for 'a' without substituting we can cancel a-b... · 2 years, 4 months ago

No.

$$a= b$$

Take $$b$$ on LHS

$$a-b = 0$$. · 2 years, 4 months ago

but why take b on LHS ??? · 2 years, 4 months ago

Just to explain you that it is zero without substitution. · 2 years, 4 months ago

is it necessary to solve a-b , i mean without solving we can cancel it · 2 years, 4 months ago

Look, if its value is zero then it is zero one cannot argue that writing it into other form willchange its value

For example let $$h = 0$$

$$\dfrac{h}{h} =?$$

You cannot say that it is just "h" so cancel it, you cannot. Because $$\frac{0}{0}$$ don't have a specific value. · 2 years, 4 months ago