Consider the Wheatstone Bridge circuit. If the resistances R1 and R2 were zero(i.e if they were not present without altering the connections) then, the ratio of resistances will be 0:0. Will the current passing through G still be zero?

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TopNewestIf \(R_1 = R_2 = 0 \Omega\), then \(CAD\) is a short. So, \(R_k\), \(R_x\), and \(G\) are shorted out of the circuit.

This means that the currents through \(R_k\), \(R_x\), and \(G\) are all \(0 A\). – Jimmy Kariznov · 3 years, 11 months ago

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No current will pass through points CD, as the equivalent resistance between those points would be \[R_{eq}=\frac{0[R_k+R_x]}{0+ R_k+R_x} = 0\]. And since resistance is zero, no current will flow through \(CD\). – Akshat Jain · 3 years, 11 months ago

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YES – Swarali Patil · 2 years, 3 months ago

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yes? – Mario Vale · 2 years, 3 months ago

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0 – Saransh Upadhyaya · 2 years, 8 months ago

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zero A – Ahmed Elgazar · 3 years, 11 months ago

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