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3 Resistance Wheatstone Bridge

Consider the Wheatstone Bridge circuit. If the resistances R1 and R2 were zero(i.e if they were not present without altering the connections) then, the ratio of resistances will be 0:0. Will the current passing through G still be zero?

Note by Rajath Krishna R
3 years, 5 months ago

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If \(R_1 = R_2 = 0 \Omega\), then \(CAD\) is a short. So, \(R_k\), \(R_x\), and \(G\) are shorted out of the circuit.

This means that the currents through \(R_k\), \(R_x\), and \(G\) are all \(0 A\). Jimmy Kariznov · 3 years, 5 months ago

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No current will pass through points CD, as the equivalent resistance between those points would be \[R_{eq}=\frac{0[R_k+R_x]}{0+ R_k+R_x} = 0\]. And since resistance is zero, no current will flow through \(CD\). Akshat Jain · 3 years, 5 months ago

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YES Swarali Patil · 1 year, 9 months ago

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yes? Mario Vale · 1 year, 9 months ago

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0 Saransh Upadhyaya · 2 years, 2 months ago

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zero A Ahmed Elgazar · 3 years, 5 months ago

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