THIS IS THE 3RD DAY I AM POSTING PROBLEMS FOR DISCUSSIONS .....HAPPY PROBLEM SOLVING....THANKS FOR ALL JOINING....
4 years, 5 months ago
Is the answer B? First you arrange A,E,O, (in that particular order) into 8 space, so 8C3. Then you arrange the final distinct 5 letters without restrictions in the last 5 spaces available, 5!. So 8C3*5!
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o.k....then your thinking and answer is perfect and transparent.....here you see, others are having same viewpoint and opinion.......thanks Kee W.L........
thanx for communication....
actually,on my part,....i don't know what's the exact answer.....BUT YOUR DESCRIPTION REGARDING THE QUESTION IS SOUNDING TO BE RIGHT ALONG WITH THE ANSWER TOO....i too thought in the same way and got the answer (B) but also thought that there may be some faults in my thinking....here you are also supporting my thinking procedure....However keep in touch....to see whether others of the friends meet at the same point of argument.........:)
B.solution is:if we arrange a,e,o into 8 spaces in a particular order , we get 8c3 possible ways.then arrange the remaining numbers with no restriction,so 5! possible ways.so the answer is 8c3*5!
I agree with Kee Wei L.
ans is b because choose three letters a,e,o from 8 letters as 8c3 and left five letters can be rearranged can be in 5 !
yes u r right....:)