Waste less time on Facebook — follow Brilliant.
×

4TH day: SOLVE THIS INTERESTING PROBLEM

I SAID,I WOULD POST A QUESTION DAILY FOR DISCUSSING AMONG YOURSELVES..... SO HERE IS A NEW PROBLEM FOR TODAY.....THANKS TO ALL WHO JOINS THIS DISCUSSIONS .....WISHING ALL THE BEST.......:-)

Note by Raja Metronetizen
4 years, 5 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

I AM HERE GIVING THE SOLUTION......TODAY I WOULD POST A NEW QUESTION....:).... If the integer is 1 its probability is log(1),if the integer is 2 its probability is log(2),if the integer is 3 its probability is log(3)……likewise if the integer is n then its probability is log(n)……..let A denote the statement that the chosen number is even…..and B denote the statement that the chosen number is 2…. So (A intersection B)=2……hence the required probability is P(B/A)=[P(A intersection B)]/P(A)=P(B)/P(A)=log(2)/[log(2)+log(4)+log(6)+log(8)+…….log(2n)] =log(2)/log[(2^n)n!]=log(2)/[nlog(2)+log(n!)]………….thanx for joining....:).....try my new problem.....

Raja Metronetizen - 4 years, 5 months ago

Log in to reply

I am getting the answer as \(\frac{log(2)}{n*log(2) + log(n!)}\)

Saurabh Dubey - 4 years, 5 months ago

Log in to reply

mine is the same.....then, you are right absolutely........could you prove your result.......??......:)

Raja Metronetizen - 4 years, 5 months ago

Log in to reply

Should not the answer be \( \frac {log(2)}{n} \)?

Aditya Parson - 4 years, 5 months ago

Log in to reply

Since number of positive even integers for first \(2n\) numbers is simply \(\frac{2n}{2}=n\). And, probability of getting 2 from all even integers can be expressed as \(\frac{log 2}{n}\), according to the question

Aditya Parson - 4 years, 5 months ago

Log in to reply

sorry,your understanding about the question is wrong....please go through the question minutely.....you have not understood it......try it...best of luck....:)

Raja Metronetizen - 4 years, 5 months ago

Log in to reply

@Raja Metronetizen Can you point out my mistake, given that you have already solved it.

Aditya Parson - 4 years, 5 months ago

Log in to reply

@Aditya Parson i have already solved it.....:)...here you must think of conditional probability......that's my last hint.....try to think of this statement.......when we pick a number it is 2 given that the number is even........now i have almost said you what to do.......best of luck.....:)

Raja Metronetizen - 4 years, 5 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...