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A 19 year old boy from Nigeria discovered his own formula in mathematics.

A 19 year old boy named Ayanlaja Ramoni Adebola from Nigeria has just discovered is own mathematical formula for solving mathematical problem of a^x=bx. A question was asked by his friend to him which brought his research to find the solution to the mathematical problem. He was asked to find the value of x in the equation 4^x=8x.He had to make research on such questions hoping they exist. But he discovered that most people know that the answer was 2 but what is the solution(workings) to the problem? Some made use of graph method, some made use of Eisten Raph method but he noticed most people had to limit the value of 2 because they already knew the answer was 2.

He made his research on such question and concluded there must be workings leading to the solution of the problem.

By his handwork he proposed his own formula which he named "Debo's formula". Which states that for the equation a^x=bx, then x={log{b/loga)} /loga. (where x is approximated to a whole number).

Chek out the solution of 4^x=8x using Debo's formula.
a=4 and b=8
Debo's formula ==>x=log{b/loga} divided by log a
X=log{8/log4} /log4
X=log{8/0.6021} /log4
X=log 13.2868/log4
X=1.86=2(Approximate to the nearest whole number)
Thus, using Debo's formula x=2. Proof that x=2 from Debo's formula
His friends argued that his formula can only be used to solve 4^x=8x...Another question of that type was created.
Solve 3^x=9x
Using Debo's formula
a=3 and b=9
x=log{b/loga} divided by loga x=log{9/log3) divided by log3
x=log(9/0.4771) /log3
x=log18. 864/log3
x=2.67=3(approximate to nearest whole number)
X=3 using Debo's formula.
Proof ==>
3 27=27
Using Debo's formula
Another problem was created
Using Debo's formula
a=8 and b=32
Debo's formula ==>x=log{b/loga} divided by loga
x=log{32/log8} /log8
x=log {32/0.9031}/log 8 X=log 35.43/log8
X=1.7=2(Approximate to the nearest whole number)
Using Debo's formula x=2 Proof that x=2
8^2=32 * 2
The conditions in using Debo's formula are both the LHS and RHS numeric value must be both even or both odd. Also the numeric value at exponential part (a^x) must be lesser and be divisible by the numeric value of the side with identity x. Thus in a^x=bx, a<b and a divisible by b to give a whole number. Lastly they must not be equal. So Debo later concluded that if the problem was in form of a^x=ax or b^x=bx or c^x=cx.. He concluded that x=1 must be among the solution to such problem.
Thus, 4^x=4x
Debo concluded that x=1 using his idea.
He later said Debo's formula can't be used to solve problems in form of a^x=ax cos the numeric digit of both Left hand side and Right hand side are equal because "a is in the left hand side and a is also on the right hand side" he concluded that x=1.
But if the equation is in form of a^x=bx
You can see that the numeric value of the Left hand side (a) is different from the numeric value of the right hand side =(b).
He concluded that Debo's formula is applicable to such equation.
For comments or observation or conversation concerning Debo's formula add him on Facebook with Ayanlaja Adebola Debo.

Note by Ayanlaja Adebola
1 year, 1 month ago

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Good stuff home boy . Keep up Peter Muthoga · 1 year, 1 month ago

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Awesome brother Vaibhav Varshney · 1 year, 1 month ago

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