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A few properties for solving eclipse problems

For an eclipse centered at the origin \(\dfrac { {x }^{ 2} }{ { a }^{ 2} } +\dfrac { {y }^{ 2} }{ { b}^{ 2} } =1\):

  1. Any point \(P\) on the eclipse can be expressed as \((a\cos\theta ,b\sin\theta )\) (or \((a\sin\theta ,b\cos\theta )\));

  2. Equation of the line tangent to the eclipse through point P is \(\dfrac {x\cos\theta }{a } +\dfrac {y\sin\theta }{b } =1\);

  3. The distance from the origin to the line \(ax + by = c \) is \(\left|\dfrac { c }{ \sqrt { { a }^{2 }+{ b }^{ 2 } } } \right|\);

image credit: jatin yadav.

Note by Minjie Lei
1 year, 11 months ago

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  Easy Math Editor

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Wow nice! You should put them in the wiki here!

Pi Han Goh - 1 year, 11 months ago

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