A hypothesis in Number Theory

Lately, while I was practicing for my JEE examination I discovered an amusing fact. I would like to share it with the Brilliant Community as a hypothesis.

The Hypothesis

Given a number pp, any number NN of the form:

1. n(n1)(n+1)(n2)(n+2)(np12)(n+p12)n(n-1)(n+1)(n-2)(n+2)\dots (n-\frac{p-1}{2})(n+\frac{p-1}{2}) is always divisible by pp if pp is odd. (nnatural numbers)\left(n\in \text{natural numbers}\right)

2. n(n1)(n+1)(n+2)(n2)(np2)n(n-1)(n+1)(n+2)(n-2)\dots (n -\frac{p}{2}) is always divisible by pp if pp is even. (nnatural numbers)\left(n\in \text{natural numbers}\right)

My motivation towards the hypothesis

We know that any natural number NN(if want to write it with respect to pp) can be of only the following forms:{kp,kp+1,kp+2,kp+p1}\{kp, kp+1, kp+2,\dots kp+p-1\} where kk is a whole number. Now I tried to write an expression for NN such that, no matter what form of number from the above set we put in that expression for NN, it is always divisible by pp and that's how I got to those two expressions written above!

So what's the use of this hypothesis

This hypothesis has helped me solve quite a number of problems in a sweet and simple fashion. It has at many places helped me reduce certain calculations. It certainly helps you solve problems where NN is given to you as a function of nn and you are asked to find the divisibilty of NN by a certain number. These are a fews ways where this hypothesis can be a bit resourceful!


What I want from the Brilliant community is to help me come up with a more refined form of the two expressions if possible and some other amusing observation which when supplemented to this hypothesis can be highly useful. Do comment and share about how you felt about this note. Give as many inputs as possible, this will only help us all grow as a science community.

This was my first note and I will be highly grateful to the community if they provide feedbacks which can help me refine my note writing skills.

Thank you!

Note by Miraj Shah
5 years ago

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Your hypothesis is certainly correct, and a weaker version of the well known result that the product of n consecutive integers is divisible by n! .

Soumava Pal - 5 years ago

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