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# A math

cos1 * cos2 * cos3 * ........* cos149 * cos150 =?

Note by Eraz Ahmed
4 years, 5 months ago

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Assuming that the angles are in degrees, the result is zero since $$\cos (90)=0$$. · 4 years, 5 months ago

Here's a similar problem that I believe most of you have seen.

Simplify $$(x-a)(x-b)(x-c) \cdots (x-z)$$. Staff · 4 years, 5 months ago

0 · 4 years, 5 months ago

if the angles are in degrees then answer is obviously 0. but i don't think they meant that. i think angles are in radians , then the answer would be approx: -1.14893 * 10^-46 · 4 years, 5 months ago

i have used degree values here don't use radians.... · 4 years, 5 months ago

haroun M 's answer is correct,think easily because it's so much easy · 4 years, 5 months ago

Yes but one hour later than I posted... · 4 years, 5 months ago

0 · 4 years, 5 months ago

0 · 4 years, 5 months ago

approx -1.14893 * 10^-46 · 4 years, 5 months ago

how??? · 4 years, 5 months ago

maybe he take it in radian. · 4 years, 5 months ago

0 · 4 years, 5 months ago

hello, the result is very ugly $$-1.14893012274526133709121721740219091292398251438476437266\times10^{-46}$$

Sonnhard. · 4 years, 5 months ago

how?please explain · 4 years, 5 months ago