I keep on disputing numerous problems of this type. I don't understand why the answer is so obvious to the author.

In my opinion, these questions are not really good.

I'll take Spiked Math's help to illustrate this out:

Moral:There are infinite formulae that fits a finite number of elements. There is no best fit formula. It is just your perception

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Fit this polynomial – Krishna Sharma · 2 years, 1 month ago

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"very logic"

LMAO!!! – John Muradeli · 2 years ago

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Find the next number of the sequence

\(1, 1, 1, 120, ?\)

Ans: \(25852016738884976640000\), because

\(\Gamma (\Gamma (1))=1\)

\(\Gamma (\Gamma (2))=1\)

\(\Gamma (\Gamma (3))=1\)

\(\Gamma (\Gamma (4))=120\)

\(\Gamma (\Gamma (5))=25852016738884976640000\) – Michael Mendrin · 2 years, 1 month ago

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– Pi Han Goh · 1 year, 10 months ago

Oh man, I just saw this post, I should have used this for TKC.Log in to reply

Hi; whenever I see those type questions I always just fit a polynomial through them. Admittedly, it was tough with Q2. – Bobbym None · 2 years, 1 month ago

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– Agnishom Chattopadhyay · 2 years, 1 month ago

:D I agree with you. I fit the polynomial too. But when I try to enter the answer, Brilliant says that only integer values are allowed.Log in to reply

Loved it . – Azhaghu Roopesh M · 2 years ago

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So, here's the ultimate way to cure this problem:

Let us come up with a way to put a polynomial through any set of inputs and outputs x and y.

Any clues?

For example, I defined one as follows:

Find the next number in the sequence: \(0,0,0,0,0,0,0,0,0,__\)

Ans: 10!

Now if there was a way to, say, put a function through something like 1, 4, 9, 16, 25, __ - that'd be great. – John Muradeli · 2 years ago

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replace {1,4,9,16} with a set of your own data – Agnishom Chattopadhyay · 2 years ago

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Well I am against those" odd number out of the set" type questions. I mean there we will always be able to choose a suitable prime p for which any 3 are quadratic residues while left one isn't – Subrata Saha · 2 years, 1 month ago

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1,3, and guess what's next? Something incomputable. Its the tree function. Next, 1, 1, 2, and guess what? Depends on the number of !'s. 0!!...=1, 1!!...=1, 2!!...=2, 3!!...=??? – Aloysius Ng · 2 years, 1 month ago

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