All has read about transistors. I guess I(E)=I(B)+I(C) is known to all. Now there is going to be added a new proof to it. 5=2+3 Taking alphabetic system, we write it as E=B+C Multiplying by I on both sides, we get IE= IB+IC Which is the law itself.
All has read about transistors. I guess I(E)=I(B)+I(C) is known to all. Now there is going to be added a new proof to it. 5=2+3 Taking alphabetic system, we write it as E=B+C Multiplying by I on both sides, we get IE= IB+IC Which is the law itself.
Note by
Shyambhu Mukherjee
1 year, 5 months ago
Problem Loading...
Note Loading...
Set Loading...
Comments
There are no comments in this discussion.