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a nice question(believe me!)

there are 4 3 -digit numbers which are equal to the sum of the cubes of their digits three of them are: 153 ,370 and 407 which is the fourth one? hint: it is very easy!

Note by Snehdeep Arora
4 years, 5 months ago

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\(371\)

Since \(3^{3} + 7^{3} + 0^{3} = 370\)

Then \(3^{3} + 7^{3} + 1^{3} = 371\) Pi Han Goh · 4 years, 5 months ago

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@Pi Han Goh correct! Snehdeep Arora · 4 years, 5 months ago

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They are known as Armstrong Numbers in popular recreational math nomenclature. Abhishek De · 4 years, 5 months ago

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