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# A nice way to frame any square number

Given that $$a<b$$ and $$a \times b=p$$

so we can put $$a<\sqrt{p}<b$$

also $$\frac{2 \times a \times b}{a + b} <\sqrt{p} < \frac{a+b}{2}$$

this is a great methode to frames any squart number increasingly precise