Let \(\Delta ABC\) be an equilateral triangle and \(P\) be a point inside this triangle such that \(PA=x,PB=y\) and \(PC=z\), If \(z^2=x^2+y^2\), find the length of the sides of \(\Delta ABC\) in terms of \(x\) and \(y\).

Let \(\Delta ABC\) be an equilateral triangle and \(P\) be a point inside this triangle such that \(PA=x,PB=y\) and \(PC=z\), If \(z^2=x^2+y^2\), find the length of the sides of \(\Delta ABC\) in terms of \(x\) and \(y\).

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestGeneral formula can be worked out to be \[\sqrt{(4 \sqrt{3} A + a^2 + b^2 + c^2)/2}\] where a, b, c are PA, PB and PC and A is a area of a triangle with side lengths a, b and c. In this case x, y, z form right angled triangle and that means that side length of the equilateral triangle is \(\sqrt{\sqrt{3} xy + x^2 + y^2}\). – Maria Kozlowska · 1 year, 11 months ago

Log in to reply

– Sualeh Asif · 1 year, 11 months ago

Can you post the method you used to find the solution?Log in to reply

Wiki – Maria Kozlowska · 1 year, 11 months ago

I have updated theLog in to reply

– Sualeh Asif · 1 year, 11 months ago

Great \(:)\)Log in to reply

Where did you got it from? Please name it. – Akshat Sharda · 1 year, 11 months ago

Log in to reply