Place an opaque "blob" of charge on a transparent, hemispherical nonconducting shell, as shown.

. Find z component of field due to it, at centre O.Do check out www.webofstories.com, listening to those great men (and women, of course) is a humbling experience.

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TopNewest@Kishore S Shenoy (vector = scalar ?) Yeah, you are right. The result is trivial, but has applications. For example, if we want to calculate field due to a hemispherical shell of charge at the centre, without messy integration. – Karthik Venkata · 5 months, 2 weeks ago

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– Kishore S Shenoy · 5 months, 2 weeks ago

Yeah, I know. That's the beauty of nature's dimensional analogy!Log in to reply

Is it \(\vec{E} = \dfrac{\sigma A}{4\pi\epsilon_0 r^2}\hat{e_z}\)? – Kishore S Shenoy · 5 months, 2 weeks ago

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