# A simple proof that 0=1

NEGATIVE 20=NEGATIVE 20
LETS BRAKE THESE NEGATIVE 20'S
16-36 AND 25-45
REWRITE LITTLE BIT MORE
4 SQUARE - 49=5 SQUARE - 59
LET US ADD A CONSTATNT BOTH THE SIDE
4 SQUARE - 49 +81/4 = 5 SQUARE - 59 +81/4
LET US FACTOR THIS NOW
4 SQUARE-249/2[9/2]SQUARE=5 SQUARE-259/2+[9/2]SQUARE
2 AND THE 9 GETS CANCELLED
FACTORISE MORE
[4-9/2] [4-9/2] = [5-9/2]] [5-9/2]
[4-9/2] SQUARE = [5-9/2] SQUARE
SAQARES AND 9/2 GET CANCELLED
SO 4=5
4-4 = 5-4 [ SUBTRACTING 4 FROM BOTH SIDE]
0=1

Note by Sai Kiran
2 years, 4 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

49 and 59 are 49 and 59 respectively

- 2 years, 4 months ago