A Unique way to find the area of a triangle

Let ABC be a general triangle.let AD,BE,CF be the medians of triangle ABC Let G be the centroid...express the area of triangle ABC in terms of AD,BE,CF... HINT: extend AG to K such that AG=GK

New Incarnation to the problem...Let p(x) be a cubic polynomial over real such that AD,BE,CF are its roots. then prove that area of triangle ABC is 1/3\sqrt{(4((x)^2-2yz)-(S2)^2} where x =sigma 2 y=sigma one z=sigma 3 S2=sum of the squares of the roots.. Hint:theory of equations,previous problem

Note by Neeraja Kirtane
3 years ago

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