Let ABC be a general triangle.let AD,BE,CF be the medians of triangle ABC Let G be the centroid...express the area of triangle ABC in terms of AD,BE,CF... HINT: extend AG to K such that AG=GK

New Incarnation to the problem...Let p(x) be a cubic polynomial over real such that AD,BE,CF are its roots. then prove that area of triangle ABC is 1/3\sqrt{(4((x)^2-2yz)-(S2)^2} where x =sigma 2 y=sigma one z=sigma 3 S2=sum of the squares of the roots.. Hint:theory of equations,previous problem

## Comments

There are no comments in this discussion.