This is a really hard functional equation by me:

Find all \(f: \mathbb{R} \rightarrow \mathbb{R}\) such that

\( f(x^2+f(y)^2)=xf(x)+yf(y) \) for all \(x,y \in \mathbb{R}\)

It looks quite simple but it's very difficult. Good luck if you try it!

This is a really hard functional equation by me:

Find all \(f: \mathbb{R} \rightarrow \mathbb{R}\) such that

\( f(x^2+f(y)^2)=xf(x)+yf(y) \) for all \(x,y \in \mathbb{R}\)

It looks quite simple but it's very difficult. Good luck if you try it!

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestsimple observations reveals f(x)=x – Hiroto Kun · 6 months, 4 weeks ago

Log in to reply

Find allmeansFind all and prove that you have all of them– Wen Z · 4 months, 3 weeks agoLog in to reply

Log in to reply

– Hiroto Kun · 6 months, 4 weeks ago

yep sure but f(x)=x is the most appropriate one :PLog in to reply

Some preliminary observations that might be useful. Will post more things as I keep progressing through.

Switch \(x\) and \(y\) around to get

\[f(x^2+f(y)^2)=x f(x)+y f(y) = f(y^2 + f(x)^2)\]

Substitute \(y=0\) to get

\[f(x^2+f(0)^2)=f(f(x)^2)\] – Sharky Kesa · 7 months ago

Log in to reply