Waste less time on Facebook — follow Brilliant.
×

I was wondering about ab! (a and b are integers, ! is factorial). Do we first multiply a and b then factorial the product or do we factorial the b and then multiply.

Note by Djordje Marjanovic
4 years, 8 months ago

No vote yet
2 votes

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Depends on the problem statement. Usually either \((\overline{ab})!, (ab)!, a\cdot b!\) is given so you don't need to worry. If it is ambigious, ask the composer. But I would treat this as \((ab)!\).

Zi Song Yeoh - 4 years, 8 months ago

Log in to reply

if you are referring to (a*b)! then you should multiply them first and then find the factorial.

Sudha Parimala - 4 years, 8 months ago

Log in to reply

If the problem states explicitly that ab is a two digit number, you should find the factorial of the two digit number. Like \(a=2,b=1\), calculate 21!.

Aditya Parson - 4 years, 8 months ago

Log in to reply

You are necessitated to multiply them first and then evaluate the factorial. Think of \((2*3)!=720\), and \(2*3!=12\). See the difference?

Shourya Pandey - 4 years, 8 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...