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Addition given above. A prefered method.

\(Exp.=1\frac{2}{3} +2\frac{5}{6}~~separate ~out~ integers ~and~fractions. \\ Exp. =1+2+\frac{2}{3}+\frac{5}{6} ~~common~ denominator~ for~ the~ fractions~ is~6\\ \therefore Exp.=3+\frac{2*2}{3*2}+\frac{5}{6}=3+\frac{9}{6}.~~~~~gcd(9,6)=3. ~\\ \frac{9}{6}=\frac{9/3}{6/3}=\frac{3}{2}=1\frac{1}{2}\\ \therefore Exp.=3 + 1\frac{1}{2}= 4\frac{1}{2} \\ Please~ note~ that ~~ n\frac{p}{q}= n+\frac{p}{q} ~~~e.g. ~~~ 106\frac{31}{89}= 106+\frac{31}{89} \)

Note by Niranjan Khanderia
2 years, 9 months ago

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