How many 3 by 3 determinants can be formed whose value is always zero , using two non zero distinct elements say a and b ??? Please help !!!

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TopNewest66 ways. – Aditya Parson · 3 years, 5 months ago

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– Raja Metronetizen · 3 years, 5 months ago

how, u came to it...?Log in to reply

– Aditya Parson · 3 years, 5 months ago

Big solution, too lousy to write it here. Is there any other way to send you my solution.?Log in to reply

– Raja Metronetizen · 3 years, 5 months ago

if you don't feel disturbed to send it to my email...metronetizen@gmail.comLog in to reply

– Aditya Parson · 3 years, 5 months ago

Sure, I will work it on paper. Please wait.Log in to reply

– Raja Metronetizen · 3 years, 5 months ago

o.k thanx...waiting for your email...Log in to reply

– Aditya Parson · 3 years, 5 months ago

Sent.Log in to reply

– Raja Metronetizen · 3 years, 5 months ago

got it....i really misunderstood the problem ....i thought that there would be only once the number " a" and "b" would be used and as the questioner said that the value would be always zero i thought that the rest terms would be zero....but you showed me my mistake.....thanx for sending...Log in to reply

– Aditya Parson · 3 years, 5 months ago

There is no mistake in it right?Log in to reply

– Raja Metronetizen · 3 years, 5 months ago

so far i understand your logic you are right ....great thinking .... (probably) no mistake in technique .....awesome....Log in to reply

– Sachin Arora · 3 years, 5 months ago

Please email the solution of this question at aryanarora02@gmail.comLog in to reply

– Aditya Parson · 3 years, 5 months ago

But the question is asked on brilliant.Log in to reply

– Sachin Arora · 3 years, 5 months ago

This question is already asked by me only .No body relplied . I posted again .Log in to reply

– Aditya Parson · 3 years, 5 months ago

are you sure it is not a question asked on brilliant? I am not able to understand what you say.Log in to reply

– Sachin Arora · 3 years, 5 months ago

I am vry sure , this question is not asked on brilliantLog in to reply

– Aditya Parson · 3 years, 5 months ago

Sent.Log in to reply

You wanted to know how many determinants can be formed....see any two determinant can be said different whether its orientation of its terms are different....you are using only 2 non zero element ,you assumed "a" and "b"...now watch that in any place out of the 9 places of a 3 by 3 determinant you put them them and as a result you would get the result zero for every representation......so there are 9 places (3 rows 3 columns ) you are choosing 2 different places out of them .....you could do this in 9C2 ways....so there should (i'm not using "would" as i am not sure for my own logic and apprehension ) be only 36 ways to form different determinant....let's see if any one backs me up for this procedure to be right or wrong...... – Raja Metronetizen · 3 years, 5 months ago

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this is a question which is asked on brilliant – Attain k Gupta · 3 years, 5 months ago

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