Am I thinking correctly ?

What is the sum of digits of (9999999999)^3 ?

Is the answer 180 ?

Note by Sharath Chandar
3 years, 9 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

how did u find that out ??

Sivaramakrishnan Sivakumar - 3 years, 9 months ago

Log in to reply

For example take (99)^3. In this sum of the number (99) is 9+9=18. Now take the cube ,which is 970299. In this the sum (9+7+0+2+9+9) is 36. I used this in the question. (9999999999)^3 has 10 nines. Therefore the sum is 90. Hence the sum of the digits of (9999999999)^3 is 180.

Sharath Chandar - 3 years, 9 months ago

Log in to reply

take 9 and 9^3 , Your logic doesn't work !

Sivaramakrishnan Sivakumar - 3 years, 9 months ago

Log in to reply

@Sivaramakrishnan Sivakumar It works.. 9^3= 729. 7+2+9= 18

Sharath Chandar - 3 years, 9 months ago

Log in to reply

@Sharath Chandar oh..ya... then i will use a computer to check !

Sivaramakrishnan Sivakumar - 3 years, 9 months ago

Log in to reply

@Sivaramakrishnan Sivakumar You may not be able to!!

Sharath Chandar - 3 years, 9 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...