on a fully solved rubik's cube make the following move continuously 10 times

you will find that first the cube get scrambled at some parts then eventually it get solved

the move is : \( R U R' F \)

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestPlease explain it more!!!!!!

Log in to reply

DTYW CI6

Log in to reply

there is nothing to explain just solve the rubik's cube and apply the given algorithm (it won't help you to solve the cube its just a magic move)

Log in to reply

All algorithms when repeated enough times on a solved cube result in a completely solved cube. You can do any specific set of moves repeatedly without moving the cube and it'll get back together eventually.

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Can you explain what R U R' F mean?

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

ok

Log in to reply

The order of a sequence of moves is a matter of determining the effect on the sub-cubes as a permutation using disjoint cycle notation, then the order is the LCM of the cycle lengths. For \(RUR'F\) the effect on the sub-cubes is a a 2-cycle on edge FR; a 5-cycle on edges UF, UL, UB, FL, and FD; and a 5-cycle on the 4 corners of the \(F\) face (FUL, FUR, and FDL), and FDR. The LCM of 2, 5, and 5 is 10. Of note would be the maximal order which is 1260 of which \(DF'DR'U^2\) is an example with shortest possible length in HTM (Half-Turn Metric, where turns of \(90^\circ, 180^\circ,\) and \(270^\circ\) are considered a single move).

Log in to reply

These moves are trivial. Any algorithm operated repeatedly on a cube will result back in the Original configuration in finite repeatitions.

Log in to reply

I can agree

Log in to reply

It can be proven mathematically

Log in to reply

Log in to reply

Those who know non commutative algebra can easily figure it out that each generator (RUR'F) forms a normal subgroup of order (here 10).

find n such that (RUR'F)^n=identity (means doing nothing on the cube) Eg: (RUR'F)^2=RUR'FRUR'F, among these some comnbinations can be replaced by other moves. Finally one can show (clever manipulations), (RUR'F)^10=Identity

Always Keep your total cube orientation in a fixed position during the moves. R- Right side face clockwise rotation U- upside face clockwise rotation R'- Right side face anti-clockwise rotation F-Front face clockwise rotation

Log in to reply

There exist much more moves like this:

L'ULU do this 5 times

U'R 62 times

UL'U'L 6 times

RU'L'U 27 times

M'U 8 times

M'UM'U' 6 times

R2L2 12 times

and many more ........................................

Happy Cubing!!!!!!!

Log in to reply

R 4 times

Log in to reply

Yes. That's the easiest "IDENTITY ALGORITHM "

Log in to reply

I found out that there are many such moves such as moving a solved cube 16 times with R U R' F B.

Log in to reply

What would be the biggest number of steps required to get a cube back in solved state for a 4-lettered algorithm...and what would be the algorithm.....i found that R'U is a big one

Log in to reply

You will have to do it 62 times...

Log in to reply

I think 63 is the number.....RU has to be done 105..

Log in to reply

You could also repeat RUR'U' 6 times to achieve the same result.

Log in to reply

Technically, this will happen no matter what sequence of moves one makes. It may take longer or shorter than 10 iterations, but because there are a finite number of positions for the cube, it has to eventually return to its original state.

Log in to reply

what does that mean

Log in to reply

6 repetitions and the cube will resolve itself.

Log in to reply

Awesome

Log in to reply

any particular move can do it not only this move :P

Log in to reply

Can you explain what is RU R' F

Log in to reply

it remains same

Log in to reply

But i didn't get it !!!

Log in to reply

R= right side clock wise U= upper side clock wise R'=right side anti-clock wise F= front side clock wise

Log in to reply

normal position

Log in to reply

Doing the same move multiple times creates a subgroup of all moves, so by lagrange's theorem, the number of time you must repeat the move divides the number of possible combinations of the rubik's cube.

Log in to reply

hey are u in fiitjee south delhi??? @Rishabh Jain

Log in to reply

no i am a commerce student from east delhi (totally opposite answer what you asked?)

Log in to reply

Let me give you one more Take a solved rubiks cube and do the following 6 times FRUR'U'F'

Log in to reply

not just only RUR'F , it works for almost all algorithms provided they are 4 moves

Log in to reply

I just did it and it does get solved

Log in to reply

Do any random move repeatedly and it will get solved eventually not for this move only

Log in to reply

@Rishabh Jain Try this, R'D'RD 6 times.. Same thing happens!

Log in to reply

how to get fully solved cube?

Log in to reply

VERRY VERRY EASY

Log in to reply

are you saying to solve the cube or about the above mentioned stuff

Log in to reply

You all can even try

R' D' R D. I think it works with almostallof the algos. The number of times you have to do it may differ.Log in to reply

you could just take a cube and keep doing U R repeatedly and get the original configuration back.....but u need to have the patience as you have to do it quite many times..

Log in to reply

Is there a way to predict how many times you have to do the move to get back to solve?

Log in to reply

You have to program it. Look at this

Log in to reply

cool. i liked it

Log in to reply

what does RU R`F mean please???

Log in to reply

R means rotating the right face clockwise.. R' means to do the same in anticlock direction... U, F, D, B, L mean up, front, down, back, and lesft respectively...

Log in to reply

it's awesome !!

Log in to reply

Am I right in thinking that the number of moves given in any algorithm with as many moves as possible but repeated over a number of times, the number of times cannot be a prime number?

Log in to reply

RU R'U'

Log in to reply

another move is F R U R'U'F'

Log in to reply

R U' x63

Log in to reply

Actually what are these 'R' 'U' 'F' ??

Log in to reply

I too don't know.

Log in to reply

Log in to reply

R x4 , R'x4 ,....

Log in to reply

TEACH ME!!!!!!!!!!

Log in to reply

It is a bunch at internets

Log in to reply

Which method do you use?

IF you use the CFOP method please tell me from where did you learn it?

I want to learn the same.Suggest me a better site for this.

Thank you :)

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply