# An elementary doubt

This doubt has been bothering me for ages. I had learnt that if we have 2 intervals $(a,b)\cup(c,d)$, we can merge these together to form $(a,d)$ as long as $a and $b>c$. However, I saw one of the teachers at my coaching institute do this: $(a,b)\ \cup(b,c)=(a,b)$ How can we merge these two intervals together? Was what I had learnt incorrect? And in general, when can we merge $2$ or $more$ intervals (of all 4 types: $(a,b],(a,b),[a,b),[a,b]$) together to form a single interval? Any help would be really, really appreciated! Thanks very, very much in advance! Note by Ishan Dasgupta Samarendra
5 years, 1 month ago

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@Brian Charlesworth Sir, @Michael Mendrin Sir, @Pranjal Jain  Sirs, please could you help me? Many thanks!  PS. I'm really sorry for bothering you.

- 5 years, 1 month ago

Yeah, that seems funny to me. If your teacher wrote

$[a,b] \cup [b,c] = [a,c]$

then that would have been fine, since $[a,b]$ is a closed interval, i.e., includes the end points. However, $(a,b)$ is an open interval, so you'd think that the point $b$ shouldn't be in the union.

I've always hated real analysis when I was in school.

- 5 years, 1 month ago

Yes, Sir, even I was surprised when I saw it was an open interval - I think this would be possible only for a closed interval.  Wow Sir, you were taught Real Analysis in your school! My Uncle did it first when he went to Swarthmore!

- 5 years, 1 month ago

Actually, I didn't have real analysis homework until I was in college, but I had read up on it long before then.

- 5 years, 1 month ago

Wish I had a millionth of your brain, Sir... Would never have to worry about anything then:)

- 5 years, 1 month ago

I'm assuming that what your teacher wrote was $(a,b) \cup (b,c) = (a,c),$ which would only be correct if $b = c,$ (which wouldn't make much sense anyway). Otherwise, as Michael has said, if $b \lt c$ then $b$ would have to be excluded from the interval "sum".

As for the other types of intervals, we would have both $(a,b] \cup (b,c) = (a,c)$ and $(a,b) \cup [b,c) = (a,c).$

- 5 years, 1 month ago

Yes, Sir, your assumption was right. Thanks so much for your help, Sir. I'm really, really grateful to you!

- 5 years, 1 month ago