An experiment

Hello, I just thought of comparing the speeds of two methods to double a number in python but didn't got a precise result. Can anyone help me improving this testing?


Here's the program:

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import time,random
mainscores=[[],[]]
for digits in range(15):
    print('Calculations with %s digit numbers are going on...' %(digits+1))
    scoreplus=0
    scoremultiply=0
    for m in range(100):
        timebyaplusa=0
        timebyatimestwo=0
        while timebyaplusa==timebyatimestwo:
            a=random.randint((10**digits),(10**(digits+1))-1)
            starttime=time.time()
            b1=a+a
            timebyaplusa+=time.time()-starttime
            starttime=time.time()
            b2=a*2
            timebyatimestwo+=time.time()-starttime
            if b1!=b2:
                print('Error')
        if timebyaplusa>timebyatimestwo:
            scoremultiply+=1
        else:
            scoreplus+=1
    mainscores[0].append(scoreplus)
    mainscores[1].append(scoremultiply)

...and here's the output:

Will it even show any difference?

Note by Pranjal Jain
3 years, 2 months ago

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1 vote

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Don't know anything about Python, but my guess is that only 1 trial per an \( n \) digit number won't tell you much, since both methods have comparable times and the random factors obfuscate any differences in the short term.

If you want to see a difference, try more trials (1000?) and average them out instead of just one trial.

Siddhartha Srivastava - 3 years, 2 months ago

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Good idea! Let me try that out.

Pranjal Jain - 3 years, 2 months ago

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Well, for 10k calculations, for \(n\) digit numbers, \(n\in \{1,2,3,\cdots,20\}\), the results were as follows:

while with 1m calculations, the results were:

Seems like '+' wins in case of bigger numbers.

Pranjal Jain - 3 years, 2 months ago

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