Suppose,you have a ribbon that can be tightly wrapped around the equatorial circumference of the earth. Now you increase its length by 1 metre. Now your job is to calculate how much high equally it can be raised all around the circumference of the earth.
I WANT THE EXACT ANSWER.BEST OF LUCK!!!
CLUE: The answer is a surprising one.

\(\Delta L=2 \pi \Delta r\), where \(\Delta r\) is the desired uniform increase in height and \(\Delta L\) is the increase in ribbon length. This is the same equation to be used in the other ribbon problem.

I used to ponder this question while running around a racetrack, intrigued how the extra distance between tracks is independent of the radius of curvature. A better question is to ask, at what latitude relative to the equator will the height increase by 1 meter for a stretched ribbon at constant length?

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewest\(\Delta L=2 \pi \Delta r\), where \(\Delta r\) is the desired uniform increase in height and \(\Delta L\) is the increase in ribbon length. This is the same equation to be used in the other ribbon problem.

I used to ponder this question while running around a racetrack, intrigued how the extra distance between tracks is independent of the radius of curvature. A better question is to ask, at what latitude relative to the equator will the height increase by 1 meter for a stretched ribbon at constant length?

Log in to reply

what ans. u got?

Log in to reply

Give me any planet or sphere in the universe and \(\Delta L = 1\) m, and the height will be \(\Delta r = \frac {1} {2 \pi} \) m.

Log in to reply

Log in to reply

1/2 pie

Log in to reply

Log in to reply

1/2 pie

Log in to reply