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# anyone can help me?

$$\frac{3}{x}-\frac{4}{y}+\frac{6}{z}=1$$

$$\frac{9}{x}+\frac{8}{y}-\frac{12}{z}=3$$

$$\frac{9}{x}-\frac{4}{y}+\frac{12}{z}=4$$

x=?

y?

z?

thank you.. :)

4 years, 6 months ago

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Let $$\frac{1}{x}=X,\frac{1}{y}=Y,\frac{1}{z}=Z$$

As such, the system of equations will be reduced to

\begin{align*} 3X-4Y+6Z &=1 \\ 9X+8Y-12Z &=3 \\ 9X-4Y+12Z &=4 \end{align*}

Solving them gives us

$X=\frac{1}{3},Y=\frac{1}{4},Z=\frac{1}{6}$

$\therefore x=3,y=4,z=6$

- 4 years, 6 months ago