# Are you a Genius, then prove it???

If you are a genius, you can solve it easily.

Use three 9's in a mathematical expression such that it forms the number one. You are not allowed to divide or multiply them.

Note by Yashasvini Sharma
7 years, 2 months ago

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MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

• bulleted
• list

1. numbered
2. list

1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

> This is a quote
This is a quote
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $2 \times 3$
2^{34} $2^{34}$
a_{i-1} $a_{i-1}$
\frac{2}{3} $\frac{2}{3}$
\sqrt{2} $\sqrt{2}$
\sum_{i=1}^3 $\sum_{i=1}^3$
\sin \theta $\sin \theta$
\boxed{123} $\boxed{123}$

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$9^{9-9}$. I guess I'm a brilliant genius. :D

- 7 years, 2 months ago

yeah..that seems to be plausible

- 7 years, 2 months ago

9^{9-9}

- 7 years, 2 months ago

i am a budding genius. :-p

- 7 years, 2 months ago

great, genius people

- 7 years, 2 months ago

9^(9-9), lol im a genius :P

- 7 years, 2 months ago

1) sgn (9+9+9)

- 7 years, 2 months ago

2) sgn (999)

- 7 years, 2 months ago

[log99.9]

- 6 years, 10 months ago

9^{9-9}

- 6 years, 1 month ago

|Log99.9|

- 6 years, 10 months ago