Are you good at BalancingBalancing?

Here's a problem I've been trying for ages.... C2H5OH+I2+OH CHI3+HCOO+H2OC_{2}H_{5}OH+ I_{2}+ OH^{-}\longrightarrow\ CHI_{3}+HCOO^{-}+H_{2}O

Question:Question: Find the stoichiometric coefficients of each of the given compounds involved in the reaction by balancing it( preferably by oxidation no.or Ion-electron method).

Do try this question and post a nice solution for it!

Thanks in advance :)!!

@ Azhaghu Roopesh M, @Ronak Aggarwal,@Pranjal Jain, @megh choski, @ Vishnuram Leonardodavinci, @ Siddhartha Srivastava,@Christopher Boo

Note by Samarpit Swain
4 years, 6 months ago

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Sorry for the way too late response dude !!!

While balancing ignore H2OH_2 O and OHOH^{-} keeping in mind that the medium is basic .(Basically we don't need them as such since they are bound to come in the scene at the end ) . Now, balance the rest i.e. C2H5OH+I2CHI3+HCOO C_{2}H_{5}OH+ I_{2} \longrightarrow CHI_{3}+HCOO^{-} , you will get 2C2H5OH+3I2+12OH 2CHI3+2HCOO+10H2O2C_{2}H_{5}OH+ 3I_{2}+ 12OH^{-}\longrightarrow\ 2CHI_{3}+2HCOO^{-}+10H_{2}O but here you'll notice that the charge is not balanced on the RHS so I think the correct answer is 2C2H5OH+3I2+12OH 2CHI3+2HCOO+10H2O+10e2C_{2}H_{5}OH+ 3I_{2}+ 12OH^{-}\longrightarrow\ 2CHI_{3}+2HCOO^{-}+10H_{2}O + 10e^{-}

A Brilliant Member - 4 years, 6 months ago

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I'm really, really sorry for the late response.

I think your method is absolutely fine, but are you sure that you can have excess electrons at the end of such reactions? I've never come across such an equation before.

Also the law of conservation of mass is violated(though negligibly), since most of the theoretical reactions give an ideal perspective.

Thanks for your inconvenience!

Samarpit Swain - 4 years, 5 months ago

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Well , I don't think we will be able to manage without the extra electrons . Do you have anything else in mind ?

@Ronak Agarwal , @Pranjal Jain , @Deepanshu Gupta : What would you guys have done ?

A Brilliant Member - 4 years, 5 months ago

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@A Brilliant Member I believe mechanism of iodoform reaction is the key.

Pranjal Jain - 4 years, 5 months ago

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@Pranjal Jain Can you explain it a bit more , please?

Samarpit Swain - 4 years, 5 months ago

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@Samarpit Swain See this. Replace R-R by H-H and the disproportionation of I2I_2 will be a bit different.

3I2+6OH5I+IO3+3H2O3I_2+6OH^-\rightarrow 5I^-+IO_3^-+3H_2O

Just add all elementary reactions to get stoichiometric coefficients.

Pranjal Jain - 4 years, 5 months ago

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@Pranjal Jain Thanks

Samarpit Swain - 4 years, 5 months ago

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Have you tried taking C2H5OH+I2CHI3 C_2H_5OH + I_2 \rightarrow CHI_3 and C2H5OHHCOO C_2H_5OH \rightarrow HCOO^- as the two half reactions and solving? Not going to post a full solution because exams.

Siddhartha Srivastava - 4 years, 6 months ago

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Yup, I've tried that way, didn't help:(

Samarpit Swain - 4 years, 6 months ago

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