Are you good at BalancingBalancing?

Here's a problem I've been trying for ages.... C2H5OH+I2+OH CHI3+HCOO+H2OC_{2}H_{5}OH+ I_{2}+ OH^{-}\longrightarrow\ CHI_{3}+HCOO^{-}+H_{2}O

Question:Question: Find the stoichiometric coefficients of each of the given compounds involved in the reaction by balancing it( preferably by oxidation no.or Ion-electron method).

Do try this question and post a nice solution for it!

Thanks in advance :)!!

@ Azhaghu Roopesh M, @Ronak Aggarwal,@Pranjal Jain, @megh choski, @ Vishnuram Leonardodavinci, @ Siddhartha Srivastava,@Christopher Boo

Note by Samarpit Swain
4 years, 9 months ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Sort by:

Top Newest

Sorry for the way too late response dude !!!

While balancing ignore H2OH_2 O and OHOH^{-} keeping in mind that the medium is basic .(Basically we don't need them as such since they are bound to come in the scene at the end ) . Now, balance the rest i.e. C2H5OH+I2CHI3+HCOO C_{2}H_{5}OH+ I_{2} \longrightarrow CHI_{3}+HCOO^{-} , you will get 2C2H5OH+3I2+12OH 2CHI3+2HCOO+10H2O2C_{2}H_{5}OH+ 3I_{2}+ 12OH^{-}\longrightarrow\ 2CHI_{3}+2HCOO^{-}+10H_{2}O but here you'll notice that the charge is not balanced on the RHS so I think the correct answer is 2C2H5OH+3I2+12OH 2CHI3+2HCOO+10H2O+10e2C_{2}H_{5}OH+ 3I_{2}+ 12OH^{-}\longrightarrow\ 2CHI_{3}+2HCOO^{-}+10H_{2}O + 10e^{-}

A Former Brilliant Member - 4 years, 8 months ago

Log in to reply

I'm really, really sorry for the late response.

I think your method is absolutely fine, but are you sure that you can have excess electrons at the end of such reactions? I've never come across such an equation before.

Also the law of conservation of mass is violated(though negligibly), since most of the theoretical reactions give an ideal perspective.

Thanks for your inconvenience!

Samarpit Swain - 4 years, 7 months ago

Log in to reply

Well , I don't think we will be able to manage without the extra electrons . Do you have anything else in mind ?

@Ronak Agarwal , @Pranjal Jain , @Deepanshu Gupta : What would you guys have done ?

A Former Brilliant Member - 4 years, 7 months ago

Log in to reply

@A Former Brilliant Member I believe mechanism of iodoform reaction is the key.

Pranjal Jain - 4 years, 7 months ago

Log in to reply

@Pranjal Jain Can you explain it a bit more , please?

Samarpit Swain - 4 years, 7 months ago

Log in to reply

@Samarpit Swain See this. Replace R-R by H-H and the disproportionation of I2I_2 will be a bit different.

3I2+6OH5I+IO3+3H2O3I_2+6OH^-\rightarrow 5I^-+IO_3^-+3H_2O

Just add all elementary reactions to get stoichiometric coefficients.

Pranjal Jain - 4 years, 7 months ago

Log in to reply

@Pranjal Jain Thanks

Samarpit Swain - 4 years, 7 months ago

Log in to reply

Have you tried taking C2H5OH+I2CHI3 C_2H_5OH + I_2 \rightarrow CHI_3 and C2H5OHHCOO C_2H_5OH \rightarrow HCOO^- as the two half reactions and solving? Not going to post a full solution because exams.

Siddhartha Srivastava - 4 years, 9 months ago

Log in to reply

Yup, I've tried that way, didn't help:(

Samarpit Swain - 4 years, 9 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...