×

# Area of a regular polygon

Could someone tell me if this formula is ok? $$N$$ is the number of sides and $$s$$ is the length of the side

Note by Andrés Dextre
1 year, 10 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

It should be $$\dfrac14 N s^2 \cot \dfrac \pi N$$.

- 1 year, 10 months ago

They're both the same

$$\tan(\frac{90^{\circ}(n-2)}{n}) = \tan( 90^{\circ} - \frac{180^{\circ}}{n}) = \cot(\frac{180^{\circ}}{n})$$

- 1 year, 10 months ago

OP wrote $$A = \dfrac19 ns^2 \tan \left( \dfrac{\text{gorn}-2}n \right )$$.

- 1 year, 10 months ago

I'll let OP clarify, but from what I see, the "9" is more likely a "4", "go" is "90" and the "r" is a bracket.

So what I thought he wrote is $$A = \frac{1}{4} ns^2 \tan( \frac{90(n-2)}{n} )$$

- 1 year, 10 months ago

If you think he wrote is true, then his expression is indeed correct. Mine is just simpler/standard.

- 1 year, 10 months ago

Thats what I wrote. Sorry about the handwritring😁

- 1 year, 10 months ago

Haha no problem!

- 1 year, 10 months ago