ASTRONAUT Curve

Sorry I posted this as a question.

Link to Desmos -https://www.desmos.com/calculator/nwyqmc0xlf \url{https://www.desmos.com/calculator/nwyqmc0xlf}

THE EQUATION IS BELOW ->

Its confusing to see but like The Batman Curve this is a product of different curves but unlike Batman Curve , you can plot this on DESMOS also!

((x18)2+(y11)22.25)((x18)2+(y7)22.25)\left(\left(\left|x\right|-18\right)^{2}+\left(y-11\right)^{2}-2.25\right)\left(\left(\left|x\right|-18\right)^{2}+\left(y-7\right)^{2}-2.25\right)

(x+182+y9.54.5+x+182y9.54.52)(x182+y9.54.5+x182y9.54.52)\left(\left|\dfrac{x+18}{2}+\dfrac{y-9.5}{4.5}\right|+\left|\dfrac{x+18}{2}-\dfrac{y-9.5}{4.5}\right|-2\right)\left(\left|\dfrac{x-18}{2}+\dfrac{y-9.5}{4.5}\right|+\left|\dfrac{x-18}{2}-\dfrac{y-9.5}{4.5}\right|-2\right)

(((x2+x223)2+(y20)2)+((x23)2+(y2+y220)2)1.5)\left(\left(\left(\dfrac{\left|x\right|-2+\left|\left|x\right|-2\right|}{23}\right)^{2}+\left(\dfrac{y}{20}\right)^{2}\right)+\left(\left(\dfrac{x}{23}\right)^{2}+\left(\dfrac{\left|y\right|-2+\left|\left|y\right|-2\right|}{20}\right)^{2}\right)-1.5\right)

(((x2+x224)2+(y21)2)+((x24)2+(y2+y221)2)1.5)\left(\left(\left(\dfrac{\left|x\right|-2+\left|\left|x\right|-2\right|}{24}\right)^{2}+\left(\dfrac{y}{21}\right)^{2}\right)+\left(\left(\dfrac{x}{24}\right)^{2}+\left(\dfrac{\left|y\right|-2+\left|\left|y\right|-2\right|}{21}\right)^{2}\right)-1.5\right)

((x+10)2+(y4)25)((x+8)2+(y8)21)(x+171+y23+x+171y232)\left(\left(x+10\right)^{2}+\left(y-4\right)^{2}-5\right)\left(\left(x+8\right)^{2}+\left(y-8\right)^{2}-1\right)\left(\left|\dfrac{x+17}{1}+\dfrac{y-2}{3}\right|+\left|\dfrac{x+17}{1}-\dfrac{y-2}{3}\right|-2\right)

(x171+y23+x171y232)\left(\left|\dfrac{x-17}{1}+\dfrac{y-2}{3}\right|+\left|\dfrac{x-17}{1}-\dfrac{y-2}{3}\right|-2\right)

(((x2+x226)2+(y427)2)+((x26)2+(y2+y2127)2)1.5)\left(\left(\left(\dfrac{\left|x\right|-2+\left|\left|x\right|-2\right|}{26}\right)^{2}+\left(\dfrac{y-4}{27}\right)^{2}\right)+\left(\left(\dfrac{x}{26}\right)^{2}+\left(\dfrac{\left|y\right|-2+\left|\left|y\right|-2\right|-1}{27}\right)^{2}\right)-1.5\right)

(105(y14)((y14)0.5(1x+181x+181)0.5((x+18)(x+18x+18)2)(x+18+1x+18+1+x+182x+182))+1)\left(10^{5}\left(y-14\right)\left(\left(y-14\right)-0.5\left(1-\dfrac{\left|\left|x+18\right|-1\right|}{\left|x+18\right|-1}\right)-0.5\left(\left(x+18\right)\left(\dfrac{\left|x+18\right|}{x+18}\right)-2\right)\left(\dfrac{\left|-\left|x+18\right|+1\right|}{-\left|x+18\right|+1}+\dfrac{\left|\left|x+18\right|-2\right|}{\left|x+18\right|-2}\right)\right)+1\right)

(105(y14)((y14)0.5(1x181x181)0.5((x18)(x18x18)2)(x18+1x18+1+x182x182))+1)\left(10^{5}\left(y-14\right)\left(\left(y-14\right)-0.5\left(1-\dfrac{\left|\left|x-18\right|-1\right|}{\left|x-18\right|-1}\right)-0.5\left(\left(x-18\right)\left(\dfrac{\left|x-18\right|}{x-18}\right)-2\right)\left(\dfrac{\left|-\left|x-18\right|+1\right|}{-\left|x-18\right|+1}+\frac{\left|\left|x-18\right|-2\right|}{\left|x-18\right|-2}\right)\right)+1\right)

(x+13.72.3+y140.5+x+13.72.3y140.52)\left(\left|\dfrac{x+13.7}{2.3}+\dfrac{y-14}{0.5}\right|+\left|\dfrac{x+13.7}{2.3}-\dfrac{y-14}{0.5}\right|-2\right)

(x13.72.3+y140.5+x13.72.3y140.52)=0\left(\left|\dfrac{x-13.7}{2.3}+\dfrac{y-14}{0.5}\right|+\left|\dfrac{x-13.7}{2.3}-\dfrac{y-14}{0.5}\right|-2\right)=0

Note by Niraj Sawant
3 months, 2 weeks ago

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This is niceeeee. How did you come up with such a beastly expression on your own???

Aaghaz Mahajan - 3 months, 2 weeks ago

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