Bonus: how would the results change if the number of people who know a random person was a skewed right distribution with a mean of 500?

Bonus: how would the results change if the number of people who know a random person was a skewed right distribution with a mean of 500?

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TopNewestIf every person with bed bugs is known by 500 other people, then 2,500 people can potentially be made to satisfy this requirement if only 1 has bed bugs. (Really it would be 501*5 = 2505 because you need to include the person who has had beg bugs but 500 is an estimate anyways) Of course, this is the worst- case scenario.

I will assume that everyone knows other people at random, which is VERY not true. In this case, people with bed bugs would know someone with bed bugs 1/5th of the time. Surprisingly, this seems to do almost nothing to the number, only reducing it by 1 to 2504.

I don't really know how to do much else but that's my analysis

EDIT: I forgot to account for people who know 2 people with bed bugs. This is going to be 1/25 people, or 100 per person with bed bugs. I think this actually makes it worse, 2,600. I'm sure this number is worse than it should be. – Alex Li · 1 month, 1 week ago

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here.

I've done a little work on this and posted a problem on itI'm having problems simulating the most random case, where no two people are known by two other people (posted here). – Trevor Arashiro · 1 month, 1 week ago

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