The generel form would be -( 2^(n+2) ) -1 where n is the number of brackets
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Aditya Kumar
·
1 year, 4 months ago

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I would rewrite this as a sequence, where \(a_{1}=1+2, a_{2}=1+2(1+2)\) and so on. finding the values of each term would give you 3,7,15,31... and this ends up being \(a_{n}=2^{n+1} -1\). Therefore, the value you are finding for this problem would be \(2^{2018}-1\). Hope this is correct and if it's not, tell me and I will revise it :D
–
Margaret Zheng
·
1 year, 6 months ago

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TopNewestThe generel form would be -( 2^(n+2) ) -1 where n is the number of brackets – Aditya Kumar · 1 year, 4 months ago

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I would rewrite this as a sequence, where \(a_{1}=1+2, a_{2}=1+2(1+2)\) and so on. finding the values of each term would give you 3,7,15,31... and this ends up being \(a_{n}=2^{n+1} -1\). Therefore, the value you are finding for this problem would be \(2^{2018}-1\). Hope this is correct and if it's not, tell me and I will revise it :D – Margaret Zheng · 1 year, 6 months ago

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– Shithil Islam · 1 year, 6 months ago

Oh, now I get it. You are right :) :)Log in to reply

– Margaret Zheng · 1 year, 6 months ago

Thanks and I am so glad that you got it!Log in to reply

2^2018-1 – Asif Mujawar · 1 year, 7 months ago

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– Shithil Islam · 1 year, 7 months ago

How can i find it? Please describe meLog in to reply