its too simple, what u have to do is:-
we know that (or can easily proof that) sin(A+B)=cosAsinB+cosBsinA,
hence sin2A=sin(A+A)=cosAsinA+cosAsinA=2cosAsinA
hence proved.....
–
Mrigank Krishan
·
1 year, 10 months ago

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Will the sum and difference of sine considered here? :)
–
Marc Vince Casimiro
·
1 year, 10 months ago

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TopNewestits too simple, what u have to do is:- we know that (or can easily proof that) sin(A+B)=cosAsinB+cosBsinA, hence sin2A=sin(A+A)=cosAsinA+cosAsinA=2cosAsinA hence proved..... – Mrigank Krishan · 1 year, 10 months ago

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Will the sum and difference of sine considered here? :) – Marc Vince Casimiro · 1 year, 10 months ago

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