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Calculus operators

Please help me to clear why dy/dx is considered to be as a ratio tho d/dx is itself a operator to find the variation with respect to x .. can it be extended upto higher derivatives and can they still be used as mere ratios for eg d^2y/(dx)^2 say some constant c then can we use (dx)^2/d^2y as 1/c .. !! i know that the last doesnt makes any sense but if for first i.e. dy/dx is say c then dx/dy is 1/c ..... then what follows after that which forces the higher derivatives not to behave the same as for first derivatives..!! any help is appreciated.. !! :)

Note by Ramesh Goenka
3 years, 9 months ago

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had done many problems with single derivatives where dy/dx is considered as a ratio.. for finding dx/dy .. we simply reciprocate the dy/dx value.. i m asking y it's considered as a ratio.. ? · 3 years, 9 months ago