# Calculus operators

Please help me to clear why dy/dx is considered to be as a ratio tho d/dx is itself a operator to find the variation with respect to x .. can it be extended upto higher derivatives and can they still be used as mere ratios for eg d^2y/(dx)^2 say some constant c then can we use (dx)^2/d^2y as 1/c .. !! i know that the last doesnt makes any sense but if for first i.e. dy/dx is say c then dx/dy is 1/c ..... then what follows after that which forces the higher derivatives not to behave the same as for first derivatives..!! any help is appreciated.. !! :)

Note by Ramesh Goenka
4 years, 7 months ago

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had done many problems with single derivatives where dy/dx is considered as a ratio.. for finding dx/dy .. we simply reciprocate the dy/dx value.. i m asking y it's considered as a ratio.. ?

- 4 years, 7 months ago

As Far As i know !! basically derivatives are not ratios !!! they are operators Or function performer !!! so u can not say them a ratio !! means + ( addition ) is an operator w.r.t. addition !!! so as the meaning of dx/dy woul change drastically !!! because it would change the dependent variable w.r.t independent variable !! so one can nevr say dy/dx =1/dx/dy simple it means !! and also it describes its deflecting behaviour for highr derivatives

- 4 years, 7 months ago