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# Can Anyone Help Me?

I saw numerous problems in Brilliant where the users posted LaTex equations like the following:

$\begin{array} { l l l l l } & & A & B & C & D & E & F \\ \times & & & & & & & 4 \\ \hline & & F & E & D & C & B & A \\ \end{array}$

Can anyone tell me how to make my own equation in this form?

I will be grateful!

Note by Victor Paes Plinio
2 years, 10 months ago

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If you hover your mouse over the Latex image, you can see the code for it.

For problems, you can select "Toggle Latex" from the "Dot dot dot" menu, and that will allow you to see it directly and copy/paste it. For example, the latex code (properly spaced) is:

\ begin{array} { l l l l l }
& & A & B & C & D & E & F \\
\times & & & & & & & 4 \\
\hline & & F & E & D & C & B & A \\
\end{array}

What this means:

• \begin{array} ... \end{array} means that we are in an "array" display
• { l l l l l } (5 letter l's) means that we are creating 5 columns that are left aligned. (Note that we actually have more columns than 5, and they are automatically left aligned.) You can use "c" and "r" for center and right-aligned respectively. You can add "|" to denote that a vertical line is to be drawn between the columns.
• & & A & B & C & D & E & F \\ - That is telling you how to create the first line. Each & denotes a seperator.
• \hline means that we are creating a horizontal line

Staff - 2 years, 10 months ago

@Calvin Lin Thank You Sir! But can you explain more clearly about the columns aligned? I tried to make my own equation code, but I'am confused about the number of separatos (&) and the number of columns aligned (the l's). They have a thing in common? For example: if I want to make a 3 column sum, where 2 columns have the numbers and the third column have a times sign. I wrote the code like the following, but it not appears correctly. What's my mistake?

$\begin{array} { l l l } & & 1 & 2 \ \times & 5 & 0 \ \hline 6 & 0 & 0 \ \end{array}$

- 2 years, 10 months ago

the issue with your code is that you need to use \\ to end a line instead of just one \. That did not display correctly in my original post, and I've edited it.

Staff - 2 years, 10 months ago

\begin{array} { l l l } & & 1 & 2 \ \times & 5 & 0 \ \hline 6 & 0 & 0 \ \end{array}

will give

$\begin{array} { l l l } & & 1 & 2 \\ \times & 5 & 0 \\ \hline 6 & 0 & 0 \\ \end{array}$

Note that you have an additional & in the first line, which is why 1 2 appears off to the right.

Staff - 2 years, 10 months ago

@Calvin Lin Thank you very much Sir! $$:)$$

$\begin{array} { l l l l } & 1 & 1 & 1 \\ \times & & & 3 \\ \hline & 3 & 3 & 3 \\ \end{array}$

- 2 years, 10 months ago