New user? Sign up

Existing user? Log in

please can anyone solve this problem FIND - x

-2abx = a^2(b+x) + b^2(a+x) + x^2(a+b)

Note by Palash Som 3 years, 6 months ago

Easy Math Editor

*italics*

_italics_

**bold**

__bold__

- bulleted- list

1. numbered2. list

paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)

> This is a quote

This is a quote

# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"

2 \times 3

2^{34}

a_{i-1}

\frac{2}{3}

\sqrt{2}

\sum_{i=1}^3

\sin \theta

\boxed{123}

Sort by:

Answer is given below { a }^{ 2 }b+{ a }^{ 2 }x+{ b }^{ 2 }a+{ b }^{ 2 }x+{ x }^{ 2 }a+{ x }^{ 2 }b+2abx=0 { x }^{ 2 }(a+b)+ab(a+b)+x({ a }^{ 2 }+{ b }^{ 2 }+2ab)=0 (a+b)(x+a)(x+b)=0 x=-a or -b

Log in to reply

Hint:- Rearrange as \( a^2x + b^2x + 2abx + a^2b + b^2a + x^2(a+b) = 0 \).

help!!

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestAnswer is given below { a }^{ 2 }b+{ a }^{ 2 }x+{ b }^{ 2 }a+{ b }^{ 2 }x+{ x }^{ 2 }a+{ x }^{ 2 }b+2abx=0 { x }^{ 2 }(a+b)+ab(a+b)+x({ a }^{ 2 }+{ b }^{ 2 }+2ab)=0 (a+b)(x+a)(x+b)=0 x=-a or -b

Log in to reply

Hint:- Rearrange as \( a^2x + b^2x + 2abx + a^2b + b^2a + x^2(a+b) = 0 \).

Log in to reply

help!!

Log in to reply