# can anyone help?

please can anyone solve this problem FIND - x

-2abx = a^2(b+x) + b^2(a+x) + x^2(a+b)

Note by Palash Som
3 years, 6 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Answer is given below { a }^{ 2 }b+{ a }^{ 2 }x+{ b }^{ 2 }a+{ b }^{ 2 }x+{ x }^{ 2 }a+{ x }^{ 2 }b+2abx=0 { x }^{ 2 }(a+b)+ab(a+b)+x({ a }^{ 2 }+{ b }^{ 2 }+2ab)=0 (a+b)(x+a)(x+b)=0 x=-a or -b

- 3 years, 3 months ago

Hint:- Rearrange as $$a^2x + b^2x + 2abx + a^2b + b^2a + x^2(a+b) = 0$$.

- 3 years, 6 months ago

help!!

- 3 years, 6 months ago