Find the sum of the finite series

\[ \frac{\sqrt{1} +\sqrt{2} +\sqrt{3} + \sqrt{4}+............ \sqrt{n}}{n^{2}} \],

with \(n\) being any positive integer?

Find the sum of the finite series

\[ \frac{\sqrt{1} +\sqrt{2} +\sqrt{3} + \sqrt{4}+............ \sqrt{n}}{n^{2}} \],

with \(n\) being any positive integer?

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewest\[\frac23(n+1)^{3/2}-\frac12(n+1)^{1/2}-\frac12\le\sqrt1+\dotsb+\sqrt n\le\frac23(n+1)^{3/2}-\frac12(n+1)^{1/2}\]

In other words, \(\sqrt1+\dotsb+\sqrt n=\frac23(n+1)^{3/2}-\frac12(n+1)^{1/2}-\text{error}\), where "error" is between 0 and 1/2.

Source – Akiva Weinberger · 2 years, 2 months ago

Log in to reply