Give situations to show that square root of a^2 is not equal to a. And use this to show that square root of a^2 is equal to the absolute value of a.

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I think it has something to do with induction ? Am I right ? But I dont know where to start. .. – Noel Quirol · 3 years, 2 months ago

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Start with the definition of square roots. From what I understand, you're supposed to show examples. That shouldn't be tough.

A hint that makes it really easy:

What is \(\sqrt{(-4)^2}\)? – Mursalin Habib · 3 years, 2 months ago

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Take a look at this: \(\sqrt{x }\)

Do you know what this symbol around \(x\) is called? It is called the

principal square rootoperator or sometimes simply thesquare rootoperator. Whenever people are talking aboutthesquare root of a number, they are basically talking about the principal square root.It is true that \(16\) has two square roots. One of them is \(\sqrt {16}\). The other one is \(-\sqrt{16}\). If you square both of these numbers, you are going to get \(16\).

But the principal square root of \(16\) is just \(\sqrt{16}=4\),

not\(-4\).So

thesquare root (principal) of \((-4)^2\) or \(16\) is just \(4\).I think you can take it from here. – Mursalin Habib · 3 years, 2 months ago

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– Noel Quirol · 3 years, 2 months ago

thanksssLog in to reply