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Can Specific Heats at constant pressure and volume be equal? If yes, how?

I want to know that if Cp= Cv. If it is how can we derive it?

Note by Sachin Kukreja
4 years, 9 months ago

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2 votes

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How dH = dU + Pdv???
The correct relation is
dH = dU + Pdv + Vdp

Saurabh Dubey - 4 years, 9 months ago

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but by 1st law of thermodynamics I can prove that Cp = Cv.

dH=dU + PdV

but, PV=RT (for 1 mole of gas)

P=RT/V & dH=CpdT & dU=CvdT

therefore, CpdT=CvdT + RT/V*dV

CpdTV = CvdTV + RTdV

& R=Cp-Cv

CpVdT=CvVdt + (Cp-Cv)TdV

CpVdT= CvVdT + CpTdV - CvTdV

Cp(VdT- TdV) = Cv(VdT- TdV)

therefore, Cp=Cv

Is there anything wrong I did there? Please tell me!

Sachin Kukreja - 4 years, 9 months ago

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NO!!! infact Cp=Cv+R R is gas constant.

Saurabh Dubey - 4 years, 9 months ago

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