I'll present a proof that $0 = 1$. Of-course there is an error in the proof. Can you find it?

Let us start with a vector field $\overrightarrow{v} = \dfrac{1}{r^2} \hat{r}$.

Let us find the Divergence of this field. $\overrightarrow{\nabla} . \overrightarrow{v} = \frac{1}{r^2} \frac{\partial}{\partial r} \left( r^2 \dfrac{1}{r^2} \right) = \boxed{0}$

Now let us calculate the flux of this field. $\oint_{S}{ \overrightarrow{v}. \overrightarrow{da}} = 4\pi$

Green’s Theorem state that $\int_{V} {\left (\overrightarrow{\nabla} . \overrightarrow{v} \right ) d\tau} = \oint_{S}{ \overrightarrow{v}. \overrightarrow{da}}$

Applying it we see L.H.S = 0 since $\overrightarrow{\nabla} . \overrightarrow{v} = 0$ and R.H.S = $4\pi$.

This implies $0 = 4\pi$.

Dividing by $4\pi$ we get

$\boxed{ 0 = 1 }$

Hence proved.

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## Comments

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TopNewestGreen's theorem does not hold as the divergence is not continuous inside a ball containing the origin.

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Yes , correct. To correct this error we have to use a Diract Delta Function.

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Hint 1:There is some thing fishy with the divergence.Log in to reply

@Rajdeep Dhingra is nishant abhangi better than u??

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