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Can you rigidly prove it?

Nonnegative real numbers satisfy \(a^5+b^5 \leq 1\) and \(c^5+d^5 \leq 1\). Prove that \(a^2c^3+b^2d^3 \leq 1\).

Note by Finn Hulse
2 years, 10 months ago

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