# Can you solve it?

Note by Swapnil Rajawat
4 years, 5 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

yeah this question appeared in KVPY 2012 ! The solution is easy, [Please check out the Formatting Guide since the sq root and squares are not appearing]

\sqrt{3^{2}+p^{2}} = \sqrt{2} . \sqrt{3^{2}+p^{2}-17}

3^{2} + p^{2} = 2(3^{2} + p^{2} -17)

therefore, 0 = 3^{2} + p^{2} - 34

| p | = 5

~Hence Solved~

- 4 years, 5 months ago

ok that's perfectly correct.

- 4 years, 5 months ago

thanks :D

- 4 years, 5 months ago