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Note by Swapnil Rajawat 2 years, 9 months ago

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yeah this question appeared in KVPY 2012 ! The solution is easy, [Please check out the Formatting Guide since the sq root and squares are not appearing]

Radius of director circle = \sqrt{2} radius of circle

\sqrt{3^{2}+p^{2}} = \sqrt{2} . \sqrt{3^{2}+p^{2}-17}

3^{2} + p^{2} = 2(3^{2} + p^{2} -17)

therefore, 0 = 3^{2} + p^{2} - 34

| p | = 5

~Hence Solved~ – Rohan Chandra · 2 years, 9 months ago

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@Rohan Chandra – ok that's perfectly correct. – Swapnil Rajawat · 2 years, 9 months ago

@Swapnil Rajawat – thanks :D – Rohan Chandra · 2 years, 9 months ago

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TopNewestyeah this question appeared in KVPY 2012 ! The solution is easy, [Please check out the Formatting Guide since the sq root and squares are not appearing]

Radius of director circle = \sqrt{2} radius of circle

\sqrt{3^{2}+p^{2}} = \sqrt{2} . \sqrt{3^{2}+p^{2}-17}

3^{2} + p^{2} = 2(3^{2} + p^{2} -17)

therefore, 0 = 3^{2} + p^{2} - 34

| p | = 5

~Hence Solved~ – Rohan Chandra · 2 years, 9 months ago

Log in to reply

– Swapnil Rajawat · 2 years, 9 months ago

ok that's perfectly correct.Log in to reply

– Rohan Chandra · 2 years, 9 months ago

thanks :DLog in to reply