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# Can you solve it?

Note by Swapnil Rajawat
3 years, 4 months ago

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yeah this question appeared in KVPY 2012 ! The solution is easy, [Please check out the Formatting Guide since the sq root and squares are not appearing]

\sqrt{3^{2}+p^{2}} = \sqrt{2} . \sqrt{3^{2}+p^{2}-17}

3^{2} + p^{2} = 2(3^{2} + p^{2} -17)

therefore, 0 = 3^{2} + p^{2} - 34

| p | = 5

~Hence Solved~ · 3 years, 4 months ago

ok that's perfectly correct. · 3 years, 4 months ago