# Capacitor Charge Problem

Here is a question shared by Neeraj.

I have included in the image the analysis necessary to determine the steady state capacitor charge magnitude. The Python code below uses numerical integration to compute the evolution of the capacitor charge over time. Within about 20 microseconds, the code solution converges to the known steady state solution.

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 import math dt = 10.0**(-9.0) u = 10.0**(-6.0) C = 3.0*u ###################################### t = 0.0 count = 0 VC = 0.0 I1 = (0.0 - (10.0+VC))/2.0 I2 = (0.0 - (2.0+VC))/4.0 I3 = (10.0 - (2.0+VC))/2.0 IC = I1 + I2 + I3 # IC = C*VCd VCd = IC/C while t <= 30.0*u: VC = VC + VCd*dt I1 = (0.0 - (10.0+VC))/2.0 I2 = (0.0 - (2.0+VC))/4.0 I3 = (10.0 - (2.0+VC))/2.0 IC = I1 + I2 + I3 # IC = C*VCd VCd = IC/C Q = C*VC t = t + dt count = count + 1 if count%10 == 0: print t,(abs(Q)/u) 

Note by Steven Chase
1 year, 1 month ago

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@Steven Chase try the 45th problem

- 1 year, 1 month ago

Yeah Very nice, I wanted this method only. Maybe this is long but its crazy.
Thank you so much.

- 1 year, 1 month ago

You're welcome. What is long?

- 1 year, 1 month ago

@Steven Chase The code is long for me. Maybe for you not because you are a experienced LPE.
Thanks again .

- 1 year, 1 month ago

Yeah, I think it took me about 3 minutes

- 1 year, 1 month ago

@Steven Chase it will take me minimum 10 min to type this code. You are a legend ,smart and stud.

- 1 year, 1 month ago

- 1 year, 1 month ago

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