# Capacitor Cube

If you had a cube of capacitors (each of the 12 sides was a capacitor of capacitance C) how would you find the equivalent capacitance across two outer diagonal corners?

Note by Rajath Krishna R
4 years, 10 months ago

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Run some AC through your grid.

Observe that the three vertices adjacent to one of connection points of your grid always have the same potential, due to symmetry. Since they do, you can fuse them all together into one. The same goes for the other three vertices adjacent to the other connection point.

Now you have reduced your problem to a simple configuration: (C || C || C) + (C || C || C || C || C || C) + (C || C || C) = 3C + 6C + 3C = 6/5 C

Here + means serial connection and || means parallel connection.

- 4 years, 10 months ago

This man is just superb. Solved with ease

- 1 month, 1 week ago

This webpage solves the problem with 12 resistors instead of 12 capacitors.

However, the techniques to solve this problem should be very similar.

- 4 years, 10 months ago

The link was very useful thank you....

- 4 years, 10 months ago

Can you explain it more precisely

- 11 months, 3 weeks ago