A dealer deals one card faced up. From there he draws \(n\) cards to a new pile based on the value of the first card(jacks, queens, kings, and aces are 11,12,13,1 respectively)

He continues to make piles using this method until no cards remain. What is the probability that when using this dealing method, the number of cards in the last pile are equal to the card on top of the 2nd to last pile?

I recently learned what Mathematical magic is by watching this video. My challenge for you is to create your own mathematical magic trick.

In my free time I was able to formulate my own 2-player card game. I call the game "Four kings" and the rules are as follow:

- Both players have hands of 4 cards
- Players take turns either battling or discarding a card in their hand for a new one
- To battle, each player lays down their hands then they revile them to create 4 war 'battles'
- Players takes the cards won through their war battles and discards any extra
- In the case of a draw, two cards are drawn over the equal valued cards and then battle
- If a player ends up with less than 4 four cards they draw cards until there's 4 in their hand
- The game ends when one player has 4 kings in their hand

Here are some problems involving cards

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