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A projectile is thrown at an inclination θ. A bird follows the path of the projectile maintaining a constant speed same as the initial speed of the projectile. Find the bird’s acceleration at its highest point?

Note by Ronak Pawar 3 years, 2 months ago

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Since velocity is constant we have acceleration always in the normal direction given by :

\(\frac { { v }^{ 2 } }{ R }\) where \(R\) is the radius of curvature.Now radius of curvature is given by

\(R=\frac { { v }^{ 2 }{ cos }^{ 2 }\theta }{ g } \) .Putting the values we have :

\(\boxed { a=\frac { { v }^{ 2 } }{ (\frac { { v }^{ 2 }{ cos }^{ 2 }\theta }{ g } ) } =g{ sec }^{ 2 }\theta }\)

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TopNewestSince velocity is constant we have acceleration always in the normal direction given by :

\(\frac { { v }^{ 2 } }{ R }\) where \(R\) is the radius of curvature.Now radius of curvature is given by

\(R=\frac { { v }^{ 2 }{ cos }^{ 2 }\theta }{ g } \) .Putting the values we have :

\(\boxed { a=\frac { { v }^{ 2 } }{ (\frac { { v }^{ 2 }{ cos }^{ 2 }\theta }{ g } ) } =g{ sec }^{ 2 }\theta }\)

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